Simplify 3(14÷(4^2-3^2)-5)

$3 (14 \div (4^{2} - 3^{2}) - 5)$

Simplify each term.

Rewrite the division as a fraction.

$3 (\frac{14}{4^{2} - 3^{2}} - 5)$

Simplify the denominator.

Raise $4$ to the power of $2$ .

$3 (\frac{14}{16 - 3^{2}} - 5)$

Raise $3$ to the power of $2$ .

$3 (\frac{14}{16 - 1 \cdot 9} - 5)$

Multiply $- 1$ by $9$ .

$3 (\frac{14}{16 - 9} - 5)$

Subtract $9$ from $16$ .

$3 (\frac{14}{7} - 5)$

$3 (\frac{14}{7} - 5)$

Divide $14$ by $7$ .

$3 (2 - 5)$

$3 (2 - 5)$

Simplify the expression.

Subtract $5$ from $2$ .

$3 \cdot - 3$

Multiply $3$ by $- 3$ .

$- 9$

$- 9$

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