Simplify (3-2i^3)-(8+i^2)

$(3 - 2 i^{3}) - (8 + i^{2})$

Step 1

Simplify each term.

Factor out $i^{2}$ .

$3 - 2 (i^{2} \cdot i) - (8 + i^{2})$

Rewrite $i^{2}$ as $- 1$ .

$3 - 2 (- 1 \cdot i) - (8 + i^{2})$

Rewrite $- 1 i$ as $- i$ .

$3 - 2 (- i) - (8 + i^{2})$

Multiply $- 1$ by $- 2$ .

$3 + 2 i - (8 + i^{2})$

Rewrite $i^{2}$ as $- 1$ .

$3 + 2 i - (8 - 1)$

Subtract $1$ from $8$ .

$3 + 2 i - 1 \cdot 7$

Multiply $- 1$ by $7$ .

$3 + 2 i - 7$

$3 + 2 i - 7$

Step 2

Subtract $7$ from $3$ .

$- 4 + 2 i$

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