Simplify 3/(9x^3-225x)(25-x^2)/(x^2-25)(x^2+5x)/(4x)

$\frac{3}{9 x^{3} - 225 x} \cdot \frac{25 - x^{2}}{x^{2} - 25} \cdot \frac{x^{2} + 5 x}{4 x}$

Factor $x$ out of $x^{2} + 5 x$ .

Factor $x$ out of $x^{2}$ .

$\frac{3}{9 x^{3} - 225 x} \cdot \frac{25 - x^{2}}{x^{2} - 25} \cdot \frac{x \cdot x + 5 x}{4 x}$

Factor $x$ out of $5 x$ .

$\frac{3}{9 x^{3} - 225 x} \cdot \frac{25 - x^{2}}{x^{2} - 25} \cdot \frac{x \cdot x + x \cdot 5}{4 x}$

Factor $x$ out of $x \cdot x + x \cdot 5$ .

$\frac{3}{9 x^{3} - 225 x} \cdot \frac{25 - x^{2}}{x^{2} - 25} \cdot \frac{x (x + 5)}{4 x}$

Simplify the denominator.

Factor $9 x$ out of $9 x^{3} - 225 x$ .

Factor $9 x$ out of $9 x^{3}$ .

$\frac{3}{9 x (x^{2}) - 225 x} \cdot \frac{25 - x^{2}}{x^{2} - 25} \cdot \frac{x (x + 5)}{4 x}$

Factor $9 x$ out of $- 225 x$ .

$\frac{3}{9 x (x^{2}) + 9 x (- 25)} \cdot \frac{25 - x^{2}}{x^{2} - 25} \cdot \frac{x (x + 5)}{4 x}$

Factor $9 x$ out of $9 x (x^{2}) + 9 x (- 25)$ .

$\frac{3}{9 x (x^{2} - 25)} \cdot \frac{25 - x^{2}}{x^{2} - 25} \cdot \frac{x (x + 5)}{4 x}$

Rewrite $25$ as $5^{2}$ .

$\frac{3}{9 x (x^{2} - 5^{2})} \cdot \frac{25 - x^{2}}{x^{2} - 25} \cdot \frac{x (x + 5)}{4 x}$

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x$ and $b = 5$ .

$\frac{3}{9 x (x + 5) (x - 5)} \cdot \frac{25 - x^{2}}{x^{2} - 25} \cdot \frac{x (x + 5)}{4 x}$

Simplify the numerator.

Rewrite $25$ as $5^{2}$ .

$\frac{3}{9 x (x + 5) (x - 5)} \cdot \frac{5^{2} - x^{2}}{x^{2} - 25} \cdot \frac{x (x + 5)}{4 x}$

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 5$ and $b = x$ .

$\frac{3}{9 x (x + 5) (x - 5)} \cdot \frac{(5 + x) (5 - x)}{x^{2} - 25} \cdot \frac{x (x + 5)}{4 x}$

Simplify the denominator.

Rewrite $25$ as $5^{2}$ .

$\frac{3}{9 x (x + 5) (x - 5)} \cdot \frac{(5 + x) (5 - x)}{x^{2} - 5^{2}} \cdot \frac{x (x + 5)}{4 x}$

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x$ and $b = 5$ .

$\frac{3}{9 x (x + 5) (x - 5)} \cdot \frac{(5 + x) (5 - x)}{(x + 5) (x - 5)} \cdot \frac{x (x + 5)}{4 x}$

Simplify terms.

Cancel the common factor of $3$ and $9$ .

Factor $3$ out of $3$ .

$\frac{3 (1)}{9 x (x + 5) (x - 5)} \cdot \frac{(5 + x) (5 - x)}{(x + 5) (x - 5)} \cdot \frac{x (x + 5)}{4 x}$

Cancel the common factors.

Factor $3$ out of $9 x (x + 5) (x - 5)$ .

$\frac{3 (1)}{3 (3 x (x + 5) (x - 5))} \cdot \frac{(5 + x) (5 - x)}{(x + 5) (x - 5)} \cdot \frac{x (x + 5)}{4 x}$

Cancel the common factor.

$\frac{3 \cdot 1}{3 (3 x (x + 5) (x - 5))} \cdot \frac{(5 + x) (5 - x)}{(x + 5) (x - 5)} \cdot \frac{x (x + 5)}{4 x}$

Rewrite the expression.

$\frac{1}{3 x (x + 5) (x - 5)} \cdot \frac{(5 + x) (5 - x)}{(x + 5) (x - 5)} \cdot \frac{x (x + 5)}{4 x}$

Cancel the common factor of $5 + x$ and $x + 5$ .

Reorder terms.

$\frac{1}{3 x (x + 5) (x - 5)} \cdot \frac{(x + 5) (5 - x)}{(x + 5) (x - 5)} \cdot \frac{x (x + 5)}{4 x}$

Cancel the common factor.

$\frac{1}{3 x (x + 5) (x - 5)} \cdot \frac{(x + 5) (5 - x)}{(x + 5) (x - 5)} \cdot \frac{x (x + 5)}{4 x}$

Rewrite the expression.

$\frac{1}{3 x (x + 5) (x - 5)} \cdot \frac{5 - x}{x - 5} \cdot \frac{x (x + 5)}{4 x}$

Cancel the common factor of $5 - x$ and $x - 5$ .

Rewrite $5$ as $- 1 (- 5)$ .

$\frac{1}{3 x (x + 5) (x - 5)} \cdot \frac{- 1 (- 5) - x}{x - 5} \cdot \frac{x (x + 5)}{4 x}$

Factor $- 1$ out of $- x$ .

$\frac{1}{3 x (x + 5) (x - 5)} \cdot \frac{- 1 (- 5) - (x)}{x - 5} \cdot \frac{x (x + 5)}{4 x}$

Factor $- 1$ out of $- 1 (- 5) - (x)$ .

$\frac{1}{3 x (x + 5) (x - 5)} \cdot \frac{- 1 (- 5 + x)}{x - 5} \cdot \frac{x (x + 5)}{4 x}$

Reorder terms.

$\frac{1}{3 x (x + 5) (x - 5)} \cdot \frac{- 1 (x - 5)}{x - 5} \cdot \frac{x (x + 5)}{4 x}$

Cancel the common factor.

$\frac{1}{3 x (x + 5) (x - 5)} \cdot \frac{- 1 (x - 5)}{x - 5} \cdot \frac{x (x + 5)}{4 x}$

Divide $- 1$ by $1$ .

$\frac{1}{3 x (x + 5) (x - 5)} \cdot - 1 \cdot \frac{x (x + 5)}{4 x}$

Combine $\frac{1}{3 x (x + 5) (x - 5)}$ and $- 1$ .

$\frac{- 1}{3 x (x + 5) (x - 5)} \cdot \frac{x (x + 5)}{4 x}$

Cancel the common factor of $x (x + 5)$ .

Factor $x (x + 5)$ out of $3 x (x + 5) (x - 5)$ .

$\frac{- 1}{x (x + 5) ((3) (x - 5))} \cdot \frac{x (x + 5)}{4 x}$

Cancel the common factor.

$\frac{- 1}{x (x + 5) ((3) (x - 5))} \cdot \frac{x (x + 5)}{4 x}$

Rewrite the expression.

$\frac{- 1}{(3) (x - 5)} \cdot \frac{1}{4 x}$

Multiply $\frac{- 1}{(3) (x - 5)}$ by $\frac{1}{4 x}$ .

$\frac{- 1}{(3) (x - 5) (4 x)}$

Simplify the expression.

Multiply $4$ by $3$ .

$\frac{- 1}{12 (x - 5) x}$

Move the negative in front of the fraction.

$- \frac{1}{12 (x - 5) x}$

Reorder factors in $- \frac{1}{12 (x - 5) x}$ .

$- \frac{1}{12 x (x - 5)}$

Simplify 3/(9x^3-225x)*(25-x^2)/(x^2-25)*(x^2+5x)/(4x)

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Simplify 3/(9x^3-225x)(25-x^2)/(x^2-25)(x^2+5x)/(4x)