Simplify 3 cube root of 4a^5-5 cube root of 32a^2+ cube root of (2a)^2

$3 \sqrt[3]{4 a^{5}} - 5 \sqrt[3]{32 a^{2}} + \sqrt[3]{{(2 a)}^{2}}$

Step 1

Simplify each term.

Rewrite $4 a^{5}$ as $a^{3} \cdot (4 a^{2})$ .

Factor out $a^{3}$ .

$3 \sqrt[3]{4 (a^{3} a^{2})} - 5 \sqrt[3]{32 a^{2}} + \sqrt[3]{{(2 a)}^{2}}$

Reorder $4$ and $a^{3}$ .

$3 \sqrt[3]{a^{3} \cdot 4 a^{2}} - 5 \sqrt[3]{32 a^{2}} + \sqrt[3]{{(2 a)}^{2}}$

Add parentheses.

$3 \sqrt[3]{a^{3} \cdot (4 a^{2})} - 5 \sqrt[3]{32 a^{2}} + \sqrt[3]{{(2 a)}^{2}}$

Pull terms out from under the radical.

$3 (a \sqrt[3]{4 a^{2}}) - 5 \sqrt[3]{32 a^{2}} + \sqrt[3]{{(2 a)}^{2}}$

Rewrite $32 a^{2}$ as $2^{3} \cdot (4 a^{2})$ .

Factor $8$ out of $32$ .

$3 a \sqrt[3]{4 a^{2}} - 5 \sqrt[3]{8 (4) a^{2}} + \sqrt[3]{{(2 a)}^{2}}$

Rewrite $8$ as $2^{3}$ .

$3 a \sqrt[3]{4 a^{2}} - 5 \sqrt[3]{2^{3} \cdot 4 a^{2}} + \sqrt[3]{{(2 a)}^{2}}$

Add parentheses.

$3 a \sqrt[3]{4 a^{2}} - 5 \sqrt[3]{2^{3} \cdot (4 a^{2})} + \sqrt[3]{{(2 a)}^{2}}$

Pull terms out from under the radical.

$3 a \sqrt[3]{4 a^{2}} - 5 (2 \sqrt[3]{4 a^{2}}) + \sqrt[3]{{(2 a)}^{2}}$

Multiply $2$ by $- 5$ .

$3 a \sqrt[3]{4 a^{2}} - 10 \sqrt[3]{4 a^{2}} + \sqrt[3]{{(2 a)}^{2}}$

Apply the product rule to $2 a$ .

$3 a \sqrt[3]{4 a^{2}} - 10 \sqrt[3]{4 a^{2}} + \sqrt[3]{2^{2} a^{2}}$

Raise $2$ to the power of $2$ .

$3 a \sqrt[3]{4 a^{2}} - 10 \sqrt[3]{4 a^{2}} + \sqrt[3]{4 a^{2}}$

Step 2

Add $- 10 \sqrt[3]{4 a^{2}}$ and $\sqrt[3]{4 a^{2}}$ .

$3 a \sqrt[3]{4 a^{2}} - 9 \sqrt[3]{4 a^{2}}$