Simplify (3(m)^3)/(2m^-9)

$\frac{3 {(m)}^{3}}{2 m^{- 9}}$

Step 1

Move $m^{- 9}$ to the numerator using the negative exponent rule $\frac{1}{b^{- n}} = b^{n}$ .

$\frac{3 {(m)}^{3} m^{9}}{2}$

Step 2

Multiply ${(m)}^{3}$ by $m^{9}$ by adding the exponents.

Move $m^{9}$ .

$\frac{3 (m^{9} {(m)}^{3})}{2}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{3 m^{9 + 3}}{2}$

Add $9$ and $3$ .

$\frac{3 m^{12}}{2}$