Simplify 30 root of 32d^20n^15p^25

$\sqrt[30]{32 d^{20} n^{15} p^{25}}$

Step 1

Rewrite $32 d^{20} n^{15} p^{25}$ as ${(2 d^{4} n^{3} p^{5})}^{5}$ .

$\sqrt[30]{{(2 d^{4} n^{3} p^{5})}^{5}}$

Step 2

Rewrite $\sqrt[30]{{(2 d^{4} n^{3} p^{5})}^{5}}$ as $\sqrt[6]{\sqrt[5]{{(2 d^{4} n^{3} p^{5})}^{5}}}$ .

$\sqrt[6]{\sqrt[5]{{(2 d^{4} n^{3} p^{5})}^{5}}}$

Step 3

Pull terms out from under the radical, assuming real numbers.

$\sqrt[6]{2 d^{4} n^{3} p^{5}}$