Simplify (3t-3)+(6t^2+4t+13)+(-8t^2+11t-1)

$(3 t - 3) + (6 t^{2} + 4 t + 13) + (- 8 t^{2} + 11 t - 1)$

Step 1

Remove parentheses.

$3 t - 3 + 6 t^{2} + 4 t + 13 - 8 t^{2} + 11 t - 1$

Step 2

Add $3 t$ and $4 t$ .

$7 t - 3 + 6 t^{2} + 13 - 8 t^{2} + 11 t - 1$

Step 3

Add $7 t$ and $11 t$ .

$18 t - 3 + 6 t^{2} + 13 - 8 t^{2} - 1$

Step 4

Add $- 3$ and $13$ .

$18 t + 6 t^{2} + 10 - 8 t^{2} - 1$

Step 5

Subtract $8 t^{2}$ from $6 t^{2}$ .

$18 t - 2 t^{2} + 10 - 1$

Step 6

Simplify the expression.

Subtract $1$ from $10$ .

$18 t - 2 t^{2} + 9$

Reorder $18 t$ and $- 2 t^{2}$ .

$- 2 t^{2} + 18 t + 9$