Simplify ((3x-15)/4)÷((x^2-25)/(2x-10))

$\frac{3 x - 15}{4} \div \frac{x^{2} - 25}{2 x - 10}$

To divide by a fraction, multiply by its reciprocal.

$\frac{3 x - 15}{4} \cdot \frac{2 x - 10}{x^{2} - 25}$

Simplify with factoring out.

Factor $3$ out of $3 x - 15$ .

Factor $3$ out of $3 x$ .

$\frac{3 (x) - 15}{4} \cdot \frac{2 x - 10}{x^{2} - 25}$

Factor $3$ out of $- 15$ .

$\frac{3 x + 3 \cdot - 5}{4} \cdot \frac{2 x - 10}{x^{2} - 25}$

Factor $3$ out of $3 x + 3 \cdot - 5$ .

$\frac{3 (x - 5)}{4} \cdot \frac{2 x - 10}{x^{2} - 25}$

Factor $2$ out of $2 x - 10$ .

Factor $2$ out of $2 x$ .

$\frac{3 (x - 5)}{4} \cdot \frac{2 (x) - 10}{x^{2} - 25}$

Factor $2$ out of $- 10$ .

$\frac{3 (x - 5)}{4} \cdot \frac{2 x + 2 \cdot - 5}{x^{2} - 25}$

Factor $2$ out of $2 x + 2 \cdot - 5$ .

$\frac{3 (x - 5)}{4} \cdot \frac{2 (x - 5)}{x^{2} - 25}$

Simplify the denominator.

Rewrite $25$ as $5^{2}$ .

$\frac{3 (x - 5)}{4} \cdot \frac{2 (x - 5)}{x^{2} - 5^{2}}$

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x$ and $b = 5$ .

$\frac{3 (x - 5)}{4} \cdot \frac{2 (x - 5)}{(x + 5) (x - 5)}$

Simplify terms.

Cancel the common factor of $x - 5$ .

Factor $x - 5$ out of $3 (x - 5)$ .

$\frac{(x - 5) \cdot 3}{4} \cdot \frac{2 (x - 5)}{(x + 5) (x - 5)}$

Factor $x - 5$ out of $(x + 5) (x - 5)$ .

$\frac{(x - 5) \cdot 3}{4} \cdot \frac{2 (x - 5)}{(x - 5) (x + 5)}$

Cancel the common factor.

$\frac{(x - 5) \cdot 3}{4} \cdot \frac{2 (x - 5)}{(x - 5) (x + 5)}$

Rewrite the expression.

$\frac{3}{4} \cdot \frac{2 (x - 5)}{x + 5}$

Cancel the common factor of $2$ .

Factor $2$ out of $4$ .

$\frac{3}{2 (2)} \cdot \frac{2 (x - 5)}{x + 5}$

Cancel the common factor.

$\frac{3}{2 \cdot 2} \cdot \frac{2 (x - 5)}{x + 5}$

Rewrite the expression.

$\frac{3}{2} \cdot \frac{x - 5}{x + 5}$

Multiply $\frac{3}{2}$ by $\frac{x - 5}{x + 5}$ .

$\frac{3 (x - 5)}{2 (x + 5)}$