Simplify (3x+2)/(x+4)+(x-1)/(x^2+x-12)

$\frac{3 x + 2}{x + 4} + \frac{x - 1}{x^{2} + x - 12}$

Step 1

Factor $x^{2} + x - 12$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 12$ and whose sum is $1$ .

$- 3, 4$

Write the factored form using these integers.

$\frac{3 x + 2}{x + 4} + \frac{x - 1}{(x - 3) (x + 4)}$

Step 2

To write $\frac{3 x + 2}{x + 4}$ as a fraction with a common denominator, multiply by $\frac{x - 3}{x - 3}$ .

$\frac{3 x + 2}{x + 4} \cdot \frac{x - 3}{x - 3} + \frac{x - 1}{(x - 3) (x + 4)}$

Step 3

Write each expression with a common denominator of $(x + 4) (x - 3)$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{3 x + 2}{x + 4}$ by $\frac{x - 3}{x - 3}$ .

$\frac{(3 x + 2) (x - 3)}{(x + 4) (x - 3)} + \frac{x - 1}{(x - 3) (x + 4)}$

Reorder the factors of $(x - 3) (x + 4)$ .

$\frac{(3 x + 2) (x - 3)}{(x + 4) (x - 3)} + \frac{x - 1}{(x + 4) (x - 3)}$

Step 4

Combine the numerators over the common denominator.

$\frac{(3 x + 2) (x - 3) + x - 1}{(x + 4) (x - 3)}$

Step 5

Simplify the numerator.

Expand $(3 x + 2) (x - 3)$ using the FOIL Method.

Apply the distributive property.

$\frac{3 x (x - 3) + 2 (x - 3) + x - 1}{(x + 4) (x - 3)}$

Apply the distributive property.

$\frac{3 x \cdot x + 3 x \cdot - 3 + 2 (x - 3) + x - 1}{(x + 4) (x - 3)}$

Apply the distributive property.

$\frac{3 x \cdot x + 3 x \cdot - 3 + 2 x + 2 \cdot - 3 + x - 1}{(x + 4) (x - 3)}$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ by adding the exponents.

Move $x$ .

$\frac{3 (x \cdot x) + 3 x \cdot - 3 + 2 x + 2 \cdot - 3 + x - 1}{(x + 4) (x - 3)}$

Multiply $x$ by $x$ .

$\frac{3 x^{2} + 3 x \cdot - 3 + 2 x + 2 \cdot - 3 + x - 1}{(x + 4) (x - 3)}$

Multiply $- 3$ by $3$ .

$\frac{3 x^{2} - 9 x + 2 x + 2 \cdot - 3 + x - 1}{(x + 4) (x - 3)}$

Multiply $2$ by $- 3$ .

$\frac{3 x^{2} - 9 x + 2 x - 6 + x - 1}{(x + 4) (x - 3)}$

Add $- 9 x$ and $2 x$ .

$\frac{3 x^{2} - 7 x - 6 + x - 1}{(x + 4) (x - 3)}$

Add $- 7 x$ and $x$ .

$\frac{3 x^{2} - 6 x - 6 - 1}{(x + 4) (x - 3)}$

Subtract $1$ from $- 6$ .

$\frac{3 x^{2} - 6 x - 7}{(x + 4) (x - 3)}$

Simplify (3x+2)/(x+4)+(x-1)/(x^2+x-12)

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