Simplify (3x^5-2x^3+5x)/(x^2)

$\frac{3 x^{5} - 2 x^{3} + 5 x}{x^{2}}$

Step 1

Factor $x$ out of $3 x^{5} - 2 x^{3} + 5 x$ .

Factor $x$ out of $3 x^{5}$ .

$\frac{x (3 x^{4}) - 2 x^{3} + 5 x}{x^{2}}$

Factor $x$ out of $- 2 x^{3}$ .

$\frac{x (3 x^{4}) + x (- 2 x^{2}) + 5 x}{x^{2}}$

Factor $x$ out of $5 x$ .

$\frac{x (3 x^{4}) + x (- 2 x^{2}) + x \cdot 5}{x^{2}}$

Factor $x$ out of $x (3 x^{4}) + x (- 2 x^{2})$ .

$\frac{x (3 x^{4} - 2 x^{2}) + x \cdot 5}{x^{2}}$

Factor $x$ out of $x (3 x^{4} - 2 x^{2}) + x \cdot 5$ .

$\frac{x (3 x^{4} - 2 x^{2} + 5)}{x^{2}}$

Step 2

Cancel the common factors.

Factor $x$ out of $x^{2}$ .

$\frac{x (3 x^{4} - 2 x^{2} + 5)}{x \cdot x}$

Cancel the common factor.

$\frac{x (3 x^{4} - 2 x^{2} + 5)}{x \cdot x}$

Rewrite the expression.

$\frac{3 x^{4} - 2 x^{2} + 5}{x}$