Simplify (3x)/(x^2-16)+1/(x-4)

$\frac{3 x}{x^{2} - 16} + \frac{1}{x - 4}$

Step 1

Simplify the denominator.

Rewrite $16$ as $4^{2}$ .

$\frac{3 x}{x^{2} - 4^{2}} + \frac{1}{x - 4}$

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x$ and $b = 4$ .

$\frac{3 x}{(x + 4) (x - 4)} + \frac{1}{x - 4}$

Step 2

To write $\frac{1}{x - 4}$ as a fraction with a common denominator, multiply by $\frac{x + 4}{x + 4}$ .

$\frac{3 x}{(x + 4) (x - 4)} + \frac{1}{x - 4} \cdot \frac{x + 4}{x + 4}$

Step 3

Write each expression with a common denominator of $(x + 4) (x - 4)$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{1}{x - 4}$ by $\frac{x + 4}{x + 4}$ .

$\frac{3 x}{(x + 4) (x - 4)} + \frac{x + 4}{(x - 4) (x + 4)}$

Reorder the factors of $(x - 4) (x + 4)$ .

$\frac{3 x}{(x + 4) (x - 4)} + \frac{x + 4}{(x + 4) (x - 4)}$

Step 4

Combine the numerators over the common denominator.

$\frac{3 x + x + 4}{(x + 4) (x - 4)}$

Step 5

Simplify the numerator.

Add $3 x$ and $x$ .

$\frac{4 x + 4}{(x + 4) (x - 4)}$

Factor $4$ out of $4 x + 4$ .

Factor $4$ out of $4 x$ .

$\frac{4 (x) + 4}{(x + 4) (x - 4)}$

Factor $4$ out of $4$ .

$\frac{4 (x) + 4 (1)}{(x + 4) (x - 4)}$

Factor $4$ out of $4 (x) + 4 (1)$ .

$\frac{4 (x + 1)}{(x + 4) (x - 4)}$