Simplify (3y^4-2y^2+3y-2)-(-4y^4-2y^2+3)

$(3 y^{4} - 2 y^{2} + 3 y - 2) - (- 4 y^{4} - 2 y^{2} + 3)$

Step 1

Simplify each term.

Apply the distributive property.

$3 y^{4} - 2 y^{2} + 3 y - 2 - (- 4 y^{4}) - (- 2 y^{2}) - 1 \cdot 3$

Simplify.

Multiply $- 4$ by $- 1$ .

$3 y^{4} - 2 y^{2} + 3 y - 2 + 4 y^{4} - (- 2 y^{2}) - 1 \cdot 3$

Multiply $- 2$ by $- 1$ .

$3 y^{4} - 2 y^{2} + 3 y - 2 + 4 y^{4} + 2 y^{2} - 1 \cdot 3$

Multiply $- 1$ by $3$ .

$3 y^{4} - 2 y^{2} + 3 y - 2 + 4 y^{4} + 2 y^{2} - 3$

Step 2

Simplify by adding terms.

Combine the opposite terms in $3 y^{4} - 2 y^{2} + 3 y - 2 + 4 y^{4} + 2 y^{2} - 3$ .

Add $- 2 y^{2}$ and $2 y^{2}$ .

$3 y^{4} + 3 y - 2 + 4 y^{4} + 0 - 3$

Add $3 y^{4} + 3 y - 2 + 4 y^{4}$ and $0$ .

$3 y^{4} + 3 y - 2 + 4 y^{4} - 3$

Add $3 y^{4}$ and $4 y^{4}$ .

$7 y^{4} + 3 y - 2 - 3$

Subtract $3$ from $- 2$ .

$7 y^{4} + 3 y - 5$