Simplify (3y^-4)(2y^-4)

$(3 y^{- 4}) (2 y^{- 4})$

Step 1

Rewrite using the commutative property of multiplication.

$3 \cdot 2 y^{- 4} y^{- 4}$

Step 2

Multiply $y^{- 4}$ by $y^{- 4}$ by adding the exponents.

Move $y^{- 4}$ .

$3 \cdot 2 (y^{- 4} y^{- 4})$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$3 \cdot 2 y^{- 4 - 4}$

Subtract $4$ from $- 4$ .

$3 \cdot 2 y^{- 8}$

Step 3

Multiply $3$ by $2$ .

$6 y^{- 8}$

Step 4

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$6 \frac{1}{y^{8}}$

Step 5

Combine $6$ and $\frac{1}{y^{8}}$ .

$\frac{6}{y^{8}}$