Simplify (4^0w^2)^-5

${(4^{0} w^{2})}^{- 5}$

Step 1

Anything raised to $0$ is $1$ .

${(1 w^{2})}^{- 5}$

Step 2

Multiply $w^{2}$ by $1$ .

${(w^{2})}^{- 5}$

Step 3

Multiply the exponents in ${(w^{2})}^{- 5}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$w^{2 \cdot - 5}$

Multiply $2$ by $- 5$ .

$w^{- 10}$

Step 4

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{w^{10}}$