Simplify 4^3-(|-8|*6)÷16

$4^{3} - | - 8 | \cdot 6 \div 16$

Step 1

Simplify each term.

Raise $4$ to the power of $3$ .

$64 - | - 8 | \cdot 6 \div 16$

Rewrite the division as a fraction.

$64 - \frac{| - 8 | \cdot 6}{16}$

Cancel the common factor of $6$ and $16$ .

Factor $2$ out of $| - 8 | \cdot 6$ .

$64 - \frac{2 (| - 8 | \cdot 3)}{16}$

Cancel the common factors.

Factor $2$ out of $16$ .

$64 - \frac{2 (| - 8 | \cdot 3)}{2 (8)}$

Cancel the common factor.

$64 - \frac{2 (| - 8 | \cdot 3)}{2 \cdot 8}$

Rewrite the expression.

$64 - \frac{| - 8 | \cdot 3}{8}$

The absolute value is the distance between a number and zero. The distance between $- 8$ and $0$ is $8$ .

$64 - \frac{8 \cdot 3}{8}$

Multiply $8$ by $3$ .

$64 - \frac{24}{8}$

Divide $24$ by $8$ .

$64 - 1 \cdot 3$

Multiply $- 1$ by $3$ .

$64 - 3$

Step 2

Subtract $3$ from $64$ .

$61$