Simplify (4+i)/(3-2i)

$\frac{4 + i}{3 - 2 i}$

Multiply the numerator and denominator of $\frac{4 + i}{3 - 2 i}$ by the conjugate of $3 - 2 i$ to make the denominator real.

$\frac{4 + i}{3 - 2 i} \cdot \frac{3 + 2 i}{3 + 2 i}$

Multiply.

Combine.

$\frac{(4 + i) (3 + 2 i)}{(3 - 2 i) (3 + 2 i)}$

Simplify the numerator.

Expand $(4 + i) (3 + 2 i)$ using the FOIL Method.

Apply the distributive property.

$\frac{4 (3 + 2 i) + i (3 + 2 i)}{(3 - 2 i) (3 + 2 i)}$

Apply the distributive property.

$\frac{4 \cdot 3 + 4 (2 i) + i (3 + 2 i)}{(3 - 2 i) (3 + 2 i)}$

Apply the distributive property.

$\frac{4 \cdot 3 + 4 (2 i) + i \cdot 3 + i (2 i)}{(3 - 2 i) (3 + 2 i)}$

Simplify and combine like terms.

Simplify each term.

Multiply $4$ by $3$ .

$\frac{12 + 4 (2 i) + i \cdot 3 + i (2 i)}{(3 - 2 i) (3 + 2 i)}$

Multiply $2$ by $4$ .

$\frac{12 + 8 i + i \cdot 3 + i (2 i)}{(3 - 2 i) (3 + 2 i)}$

Move $3$ to the left of $i$ .

$\frac{12 + 8 i + 3 \cdot i + i (2 i)}{(3 - 2 i) (3 + 2 i)}$

Multiply $i (2 i)$ .

Raise $i$ to the power of $1$ .

$\frac{12 + 8 i + 3 i + 2 (i^{1} i)}{(3 - 2 i) (3 + 2 i)}$

Raise $i$ to the power of $1$ .

$\frac{12 + 8 i + 3 i + 2 (i^{1} i^{1})}{(3 - 2 i) (3 + 2 i)}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{12 + 8 i + 3 i + 2 i^{1 + 1}}{(3 - 2 i) (3 + 2 i)}$

Add $1$ and $1$ .

$\frac{12 + 8 i + 3 i + 2 i^{2}}{(3 - 2 i) (3 + 2 i)}$

Rewrite $i^{2}$ as $- 1$ .

$\frac{12 + 8 i + 3 i + 2 \cdot - 1}{(3 - 2 i) (3 + 2 i)}$

Multiply $2$ by $- 1$ .

$\frac{12 + 8 i + 3 i - 2}{(3 - 2 i) (3 + 2 i)}$

Subtract $2$ from $12$ .

$\frac{10 + 8 i + 3 i}{(3 - 2 i) (3 + 2 i)}$

Add $8 i$ and $3 i$ .

$\frac{10 + 11 i}{(3 - 2 i) (3 + 2 i)}$

Simplify the denominator.

Expand $(3 - 2 i) (3 + 2 i)$ using the FOIL Method.

Apply the distributive property.

$\frac{10 + 11 i}{3 (3 + 2 i) - 2 i (3 + 2 i)}$

Apply the distributive property.

$\frac{10 + 11 i}{3 \cdot 3 + 3 (2 i) - 2 i (3 + 2 i)}$

Apply the distributive property.

$\frac{10 + 11 i}{3 \cdot 3 + 3 (2 i) - 2 i \cdot 3 - 2 i (2 i)}$

Simplify.

Multiply $3$ by $3$ .

$\frac{10 + 11 i}{9 + 3 (2 i) - 2 i \cdot 3 - 2 i (2 i)}$

Multiply $2$ by $3$ .

$\frac{10 + 11 i}{9 + 6 i - 2 i \cdot 3 - 2 i (2 i)}$

Multiply $3$ by $- 2$ .

$\frac{10 + 11 i}{9 + 6 i - 6 i - 2 i (2 i)}$

Multiply $2$ by $- 2$ .

$\frac{10 + 11 i}{9 + 6 i - 6 i - 4 i i}$

Raise $i$ to the power of $1$ .

$\frac{10 + 11 i}{9 + 6 i - 6 i - 4 (i^{1} i)}$

Raise $i$ to the power of $1$ .

$\frac{10 + 11 i}{9 + 6 i - 6 i - 4 (i^{1} i^{1})}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{10 + 11 i}{9 + 6 i - 6 i - 4 i^{1 + 1}}$

Add $1$ and $1$ .

$\frac{10 + 11 i}{9 + 6 i - 6 i - 4 i^{2}}$

Subtract $6 i$ from $6 i$ .

$\frac{10 + 11 i}{9 + 0 - 4 i^{2}}$

Add $9$ and $0$ .

$\frac{10 + 11 i}{9 - 4 i^{2}}$

Simplify each term.

Rewrite $i^{2}$ as $- 1$ .

$\frac{10 + 11 i}{9 - 4 \cdot - 1}$

Multiply $- 4$ by $- 1$ .

$\frac{10 + 11 i}{9 + 4}$

Add $9$ and $4$ .

$\frac{10 + 11 i}{13}$

Split the fraction $\frac{10 + 11 i}{13}$ into two fractions.

$\frac{10}{13} + \frac{11 i}{13}$

Simplify (4+i)/(3-2i)

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