Simplify ((4k^2+2k)(5k^2-3))/(6k)

$\frac{(4 k^{2} + 2 k) (5 k^{2} - 3)}{6 k}$

Step 1

Factor $2 k$ out of $4 k^{2} + 2 k$ .

Factor $2 k$ out of $4 k^{2}$ .

$\frac{(2 k (2 k) + 2 k) (5 k^{2} - 3)}{6 k}$

Factor $2 k$ out of $2 k$ .

$\frac{(2 k (2 k) + 2 k (1)) (5 k^{2} - 3)}{6 k}$

Factor $2 k$ out of $2 k (2 k) + 2 k (1)$ .

$\frac{2 k (2 k + 1) (5 k^{2} - 3)}{6 k}$

$\frac{2 k (2 k + 1) (5 k^{2} - 3)}{6 k}$

Step 2

Cancel the common factor of $2$ and $6$ .

Factor $2$ out of $2 k (2 k + 1) (5 k^{2} - 3)$ .

$\frac{2 ((k (2 k + 1)) (5 k^{2} - 3))}{6 k}$

Cancel the common factors.

Factor $2$ out of $6 k$ .

$\frac{2 ((k (2 k + 1)) (5 k^{2} - 3))}{2 (3 k)}$

Cancel the common factor.

$\frac{2 ((k (2 k + 1)) (5 k^{2} - 3))}{2 (3 k)}$

Rewrite the expression.

$\frac{(k (2 k + 1)) (5 k^{2} - 3)}{3 k}$

$\frac{(k (2 k + 1)) (5 k^{2} - 3)}{3 k}$

$\frac{(k (2 k + 1)) (5 k^{2} - 3)}{3 k}$

Step 3

Cancel the common factor of $k$ .

Cancel the common factor.

$\frac{k (2 k + 1) (5 k^{2} - 3)}{3 k}$

Rewrite the expression.

$\frac{(2 k + 1) (5 k^{2} - 3)}{3}$

$\frac{(2 k + 1) (5 k^{2} - 3)}{3}$

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