Simplify 4n^4*(2n^-3)

$4 n^{4} \cdot (2 n^{- 3})$

Step 1

Rewrite using the commutative property of multiplication.

$4 \cdot 2 n^{4} n^{- 3}$

Step 2

Multiply $n^{4}$ by $n^{- 3}$ by adding the exponents.

Move $n^{- 3}$ .

$4 \cdot 2 (n^{- 3} n^{4})$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$4 \cdot 2 n^{- 3 + 4}$

Add $- 3$ and $4$ .

$4 \cdot 2 n^{1}$

Step 3

Simplify $4 \cdot 2 n^{1}$ .

$4 \cdot 2 n$

Step 4

Multiply $4$ by $2$ .

$8 n$