Simplify ((4x^3-16x^2-180x)/(2x^2+10x)*(25-x^2)/(x^2-25))÷((9-x)/(-3x))

$\frac{4 x^{3} - 16 x^{2} - 180 x}{2 x^{2} + 10 x} \cdot \frac{25 - x^{2}}{x^{2} - 25} \div \frac{9 - x}{- 3 x}$

Step 1

To divide by a fraction, multiply by its reciprocal.

$\frac{4 x^{3} - 16 x^{2} - 180 x}{2 x^{2} + 10 x} \cdot \frac{25 - x^{2}}{x^{2} - 25} \frac{- 3 x}{9 - x}$

Step 2

Simplify the numerator.

Factor $4 x$ out of $4 x^{3} - 16 x^{2} - 180 x$ .

Factor $4 x$ out of $4 x^{3}$ .

$\frac{4 x (x^{2}) - 16 x^{2} - 180 x}{2 x^{2} + 10 x} \cdot \frac{25 - x^{2}}{x^{2} - 25} \frac{- 3 x}{9 - x}$

Factor $4 x$ out of $- 16 x^{2}$ .

$\frac{4 x (x^{2}) + 4 x (- 4 x) - 180 x}{2 x^{2} + 10 x} \cdot \frac{25 - x^{2}}{x^{2} - 25} \frac{- 3 x}{9 - x}$

Factor $4 x$ out of $- 180 x$ .

$\frac{4 x (x^{2}) + 4 x (- 4 x) + 4 x (- 45)}{2 x^{2} + 10 x} \cdot \frac{25 - x^{2}}{x^{2} - 25} \frac{- 3 x}{9 - x}$

Factor $4 x$ out of $4 x (x^{2}) + 4 x (- 4 x)$ .

$\frac{4 x (x^{2} - 4 x) + 4 x (- 45)}{2 x^{2} + 10 x} \cdot \frac{25 - x^{2}}{x^{2} - 25} \frac{- 3 x}{9 - x}$

Factor $4 x$ out of $4 x (x^{2} - 4 x) + 4 x (- 45)$ .

$\frac{4 x (x^{2} - 4 x - 45)}{2 x^{2} + 10 x} \cdot \frac{25 - x^{2}}{x^{2} - 25} \frac{- 3 x}{9 - x}$

Factor $x^{2} - 4 x - 45$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 45$ and whose sum is $- 4$ .

$- 9, 5$

Write the factored form using these integers.

$\frac{4 x ((x - 9) (x + 5))}{2 x^{2} + 10 x} \cdot \frac{25 - x^{2}}{x^{2} - 25} \frac{- 3 x}{9 - x}$

$\frac{4 x (x - 9) (x + 5)}{2 x^{2} + 10 x} \cdot \frac{25 - x^{2}}{x^{2} - 25} \frac{- 3 x}{9 - x}$

Step 3

Factor $2 x$ out of $2 x^{2} + 10 x$ .

Factor $2 x$ out of $2 x^{2}$ .

$\frac{4 x (x - 9) (x + 5)}{2 x (x) + 10 x} \cdot \frac{25 - x^{2}}{x^{2} - 25} \frac{- 3 x}{9 - x}$

Factor $2 x$ out of $10 x$ .

$\frac{4 x (x - 9) (x + 5)}{2 x (x) + 2 x (5)} \cdot \frac{25 - x^{2}}{x^{2} - 25} \frac{- 3 x}{9 - x}$

Factor $2 x$ out of $2 x (x) + 2 x (5)$ .

$\frac{4 x (x - 9) (x + 5)}{2 x (x + 5)} \cdot \frac{25 - x^{2}}{x^{2} - 25} \frac{- 3 x}{9 - x}$

Step 4

Simplify the numerator.

Rewrite $25$ as $5^{2}$ .

$\frac{4 x (x - 9) (x + 5)}{2 x (x + 5)} \cdot \frac{5^{2} - x^{2}}{x^{2} - 25} \frac{- 3 x}{9 - x}$

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 5$ and $b = x$ .

$\frac{4 x (x - 9) (x + 5)}{2 x (x + 5)} \cdot \frac{(5 + x) (5 - x)}{x^{2} - 25} \frac{- 3 x}{9 - x}$

Step 5

Simplify the denominator.

Rewrite $25$ as $5^{2}$ .

$\frac{4 x (x - 9) (x + 5)}{2 x (x + 5)} \cdot \frac{(5 + x) (5 - x)}{x^{2} - 5^{2}} \frac{- 3 x}{9 - x}$

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x$ and $b = 5$ .

$\frac{4 x (x - 9) (x + 5)}{2 x (x + 5)} \cdot \frac{(5 + x) (5 - x)}{(x + 5) (x - 5)} \frac{- 3 x}{9 - x}$

Step 6

Simplify terms.

Cancel the common factor of $x + 5$ .

Factor $x + 5$ out of $4 x (x - 9) (x + 5)$ .

$\frac{(x + 5) (4 x (x - 9))}{2 x (x + 5)} \cdot \frac{(5 + x) (5 - x)}{(x + 5) (x - 5)} \frac{- 3 x}{9 - x}$

Cancel the common factor.

$\frac{(x + 5) (4 x (x - 9))}{2 x (x + 5)} \cdot \frac{(5 + x) (5 - x)}{(x + 5) (x - 5)} \frac{- 3 x}{9 - x}$

Rewrite the expression.

$\frac{4 x (x - 9)}{2 x (x + 5)} \cdot \frac{(5 + x) (5 - x)}{x - 5} \frac{- 3 x}{9 - x}$

Multiply $\frac{4 x (x - 9)}{2 x (x + 5)}$ by $\frac{(5 + x) (5 - x)}{x - 5}$ .

$\frac{4 x (x - 9) ((5 + x) (5 - x))}{2 x (x + 5) (x - 5)} \cdot \frac{- 3 x}{9 - x}$

Cancel the common factor of $x$ .

Factor $x$ out of $2 x (x + 5) (x - 5)$ .

$\frac{4 x (x - 9) ((5 + x) (5 - x))}{x ((2 (x + 5)) (x - 5))} \cdot \frac{- 3 x}{9 - x}$

Factor $x$ out of $- 3 x$ .

$\frac{4 x (x - 9) ((5 + x) (5 - x))}{x ((2 (x + 5)) (x - 5))} \cdot \frac{x \cdot - 3}{9 - x}$

Cancel the common factor.

$\frac{4 x (x - 9) ((5 + x) (5 - x))}{x ((2 (x + 5)) (x - 5))} \cdot \frac{x \cdot - 3}{9 - x}$

Rewrite the expression.

$\frac{4 x (x - 9) ((5 + x) (5 - x))}{(2 (x + 5)) (x - 5)} \cdot \frac{- 3}{9 - x}$

Multiply $\frac{4 x (x - 9) ((5 + x) (5 - x))}{(2 (x + 5)) (x - 5)}$ by $\frac{- 3}{9 - x}$ .

$\frac{4 x (x - 9) ((5 + x) (5 - x)) \cdot - 3}{(2 (x + 5)) (x - 5) (9 - x)}$

Multiply $- 3$ by $4$ .

$\frac{- 12 x (x - 9) ((5 + x) (5 - x))}{(2 (x + 5)) (x - 5) (9 - x)}$

Cancel the common factor of $- 12$ and $2$ .

Factor $2$ out of $- 12 x (x - 9) ((5 + x) (5 - x))$ .

$\frac{2 (- 6 x (x - 9) ((5 + x) (5 - x)))}{(2 (x + 5)) (x - 5) (9 - x)}$

Cancel the common factors.

Factor $2$ out of $(2 (x + 5)) (x - 5) (9 - x)$ .

$\frac{2 (- 6 x (x - 9) ((5 + x) (5 - x)))}{2 (((x + 5) (x - 5)) (9 - x))}$

Cancel the common factor.

$\frac{2 (- 6 x (x - 9) ((5 + x) (5 - x)))}{2 (((x + 5) (x - 5)) (9 - x))}$

Rewrite the expression.

$\frac{- 6 x (x - 9) ((5 + x) (5 - x))}{((x + 5) (x - 5)) (9 - x)}$

Cancel the common factor of $x - 9$ and $9 - x$ .

Factor $- 1$ out of $x$ .

$\frac{- 6 x (- 1 (- x) - 9) ((5 + x) (5 - x))}{((x + 5) (x - 5)) (9 - x)}$

Rewrite $- 9$ as $- 1 (9)$ .

$\frac{- 6 x (- 1 (- x) - 1 (9)) ((5 + x) (5 - x))}{((x + 5) (x - 5)) (9 - x)}$

Factor $- 1$ out of $- 1 (- x) - 1 (9)$ .

$\frac{- 6 x (- 1 (- x + 9)) ((5 + x) (5 - x))}{((x + 5) (x - 5)) (9 - x)}$

Reorder terms.

$\frac{- 6 x (- 1 (- x + 9)) ((5 + x) (5 - x))}{(x + 5) (x - 5) (- x + 9)}$

Cancel the common factor.

$\frac{- 6 x (- 1 (- x + 9)) ((5 + x) (5 - x))}{(x + 5) (x - 5) (- x + 9)}$

Rewrite the expression.

$\frac{- 6 x \cdot (- 1) ((5 + x) (5 - x))}{(x + 5) (x - 5)}$

Cancel the common factor of $5 + x$ and $x + 5$ .

Reorder terms.

$\frac{- 6 x \cdot (- 1) ((x + 5) (5 - x))}{(x + 5) (x - 5)}$

Cancel the common factor.

$\frac{- 6 x \cdot (- 1) ((x + 5) (5 - x))}{(x + 5) (x - 5)}$

Rewrite the expression.

$\frac{- 6 x \cdot (- 1) (5 - x)}{x - 5}$

Cancel the common factor of $5 - x$ and $x - 5$ .

Rewrite $5$ as $- 1 (- 5)$ .

$\frac{- 6 x \cdot (- 1) (- 1 (- 5) - x)}{x - 5}$

Factor $- 1$ out of $- x$ .

$\frac{- 6 x \cdot (- 1) (- 1 (- 5) - (x))}{x - 5}$

Factor $- 1$ out of $- 1 (- 5) - (x)$ .

$\frac{- 6 x \cdot (- 1) (- 1 (- 5 + x))}{x - 5}$

Reorder terms.

$\frac{- 6 x \cdot - 1 (- 1 (x - 5))}{x - 5}$

Cancel the common factor.

$\frac{- 6 x \cdot - 1 (- 1 (x - 5))}{x - 5}$

Divide $- 6 x \cdot - 1 \cdot (- 1)$ by $1$ .

$- 6 x \cdot - 1 \cdot (- 1)$

Multiply.

Multiply $- 1$ by $- 6$ .

$6 x \cdot - 1$

Multiply $- 1$ by $6$ .

$- 6 x$

Simplify ((4x^3-16x^2-180x)/(2x^2+10x)*(25-x^2)/(x^2-25))÷((9-x)/(-3x))

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