Simplify (4x^3-2x^2+8x+8)÷(2x+1)

$(4 x^{3} - 2 x^{2} + 8 x + 8) \div (2 x + 1)$

Step 1

Rewrite the division as a fraction.

$\frac{4 x^{3} - 2 x^{2} + 8 x + 8}{2 x + 1}$

Step 2

Factor $2$ out of $4 x^{3} - 2 x^{2} + 8 x + 8$ .

Factor $2$ out of $4 x^{3}$ .

$\frac{2 (2 x^{3}) - 2 x^{2} + 8 x + 8}{2 x + 1}$

Factor $2$ out of $- 2 x^{2}$ .

$\frac{2 (2 x^{3}) + 2 (- x^{2}) + 8 x + 8}{2 x + 1}$

Factor $2$ out of $8 x$ .

$\frac{2 (2 x^{3}) + 2 (- x^{2}) + 2 (4 x) + 8}{2 x + 1}$

Factor $2$ out of $8$ .

$\frac{2 (2 x^{3}) + 2 (- x^{2}) + 2 (4 x) + 2 (4)}{2 x + 1}$

Factor $2$ out of $2 (2 x^{3}) + 2 (- x^{2})$ .

$\frac{2 (2 x^{3} - x^{2}) + 2 (4 x) + 2 (4)}{2 x + 1}$

Factor $2$ out of $2 (2 x^{3} - x^{2}) + 2 (4 x)$ .

$\frac{2 (2 x^{3} - x^{2} + 4 x) + 2 (4)}{2 x + 1}$

Factor $2$ out of $2 (2 x^{3} - x^{2} + 4 x) + 2 (4)$ .

$\frac{2 (2 x^{3} - x^{2} + 4 x + 4)}{2 x + 1}$