Simplify (4x^3-4+7x)-(2x^3-x-8)

$(4 x^{3} - 4 + 7 x) - (2 x^{3} - x - 8)$

Simplify each term.

Apply the distributive property.

$4 x^{3} - 4 + 7 x - (2 x^{3}) - - x - - 8$

Simplify.

Multiply $2$ by $- 1$ .

$4 x^{3} - 4 + 7 x - 2 x^{3} - - x - - 8$

Multiply $- - x$ .

Multiply $- 1$ by $- 1$ .

$4 x^{3} - 4 + 7 x - 2 x^{3} + 1 x - - 8$

Multiply $x$ by $1$ .

$4 x^{3} - 4 + 7 x - 2 x^{3} + x - - 8$

$4 x^{3} - 4 + 7 x - 2 x^{3} + x - - 8$

Multiply $- 1$ by $- 8$ .

$4 x^{3} - 4 + 7 x - 2 x^{3} + x + 8$

$4 x^{3} - 4 + 7 x - 2 x^{3} + x + 8$

$4 x^{3} - 4 + 7 x - 2 x^{3} + x + 8$

Simplify by adding terms.

Subtract $2 x^{3}$ from $4 x^{3}$ .

$2 x^{3} - 4 + 7 x + x + 8$

Add $- 4$ and $8$ .

$2 x^{3} + 7 x + x + 4$

Add $7 x$ and $x$ .

$2 x^{3} + 8 x + 4$

$2 x^{3} + 8 x + 4$

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