Simplify (4x)/(x+1)*(3x+3)/2

$\frac{4 x}{x + 1} \cdot \frac{3 x + 3}{2}$

Factor $3$ out of $3 x + 3$ .

Factor $3$ out of $3 x$ .

$\frac{4 x}{x + 1} \cdot \frac{3 (x) + 3}{2}$

Factor $3$ out of $3$ .

$\frac{4 x}{x + 1} \cdot \frac{3 (x) + 3 (1)}{2}$

Factor $3$ out of $3 (x) + 3 (1)$ .

$\frac{4 x}{x + 1} \cdot \frac{3 (x + 1)}{2}$

$\frac{4 x}{x + 1} \cdot \frac{3 (x + 1)}{2}$

Cancel the common factor of $2$ .

Factor $2$ out of $4 x$ .

$\frac{2 (2 x)}{x + 1} \cdot \frac{3 (x + 1)}{2}$

Cancel the common factor.

$\frac{2 (2 x)}{x + 1} \cdot \frac{3 (x + 1)}{2}$

Rewrite the expression.

$\frac{2 x}{x + 1} \cdot (3 (x + 1))$

$\frac{2 x}{x + 1} \cdot (3 (x + 1))$

Cancel the common factor of $x + 1$ .

Factor $x + 1$ out of $3 (x + 1)$ .

$\frac{2 x}{x + 1} \cdot ((x + 1) \cdot 3)$

Cancel the common factor.

$\frac{2 x}{x + 1} \cdot ((x + 1) \cdot 3)$

Rewrite the expression.

$2 x \cdot 3$

$2 x \cdot 3$

Multiply $3$ by $2$ .

$6 x$

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