Simplify (4y^2-18y+18)/(y^3-6y^2+9y)

$\frac{4 y^{2} - 18 y + 18}{y^{3} - 6 y^{2} + 9 y}$

Simplify the numerator.

Factor $2$ out of $4 y^{2} - 18 y + 18$ .

Factor $2$ out of $4 y^{2}$ .

$\frac{2 (2 y^{2}) - 18 y + 18}{y^{3} - 6 y^{2} + 9 y}$

Factor $2$ out of $- 18 y$ .

$\frac{2 (2 y^{2}) + 2 (- 9 y) + 18}{y^{3} - 6 y^{2} + 9 y}$

Factor $2$ out of $18$ .

$\frac{2 (2 y^{2}) + 2 (- 9 y) + 2 (9)}{y^{3} - 6 y^{2} + 9 y}$

Factor $2$ out of $2 (2 y^{2}) + 2 (- 9 y)$ .

$\frac{2 (2 y^{2} - 9 y) + 2 (9)}{y^{3} - 6 y^{2} + 9 y}$

Factor $2$ out of $2 (2 y^{2} - 9 y) + 2 (9)$ .

$\frac{2 (2 y^{2} - 9 y + 9)}{y^{3} - 6 y^{2} + 9 y}$

Factor by grouping.

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 2 \cdot 9 = 18$ and whose sum is $b = - 9$ .

Factor $- 9$ out of $- 9 y$ .

$\frac{2 (2 y^{2} - 9 (y) + 9)}{y^{3} - 6 y^{2} + 9 y}$

Rewrite $- 9$ as $- 3$ plus $- 6$

$\frac{2 (2 y^{2} + (- 3 - 6) y + 9)}{y^{3} - 6 y^{2} + 9 y}$

Apply the distributive property.

$\frac{2 (2 y^{2} - 3 y - 6 y + 9)}{y^{3} - 6 y^{2} + 9 y}$

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$\frac{2 ((2 y^{2} - 3 y) - 6 y + 9)}{y^{3} - 6 y^{2} + 9 y}$

Factor out the greatest common factor (GCF) from each group.

$\frac{2 (y (2 y - 3) - 3 (2 y - 3))}{y^{3} - 6 y^{2} + 9 y}$

Factor the polynomial by factoring out the greatest common factor, $2 y - 3$ .

$\frac{2 ((2 y - 3) (y - 3))}{y^{3} - 6 y^{2} + 9 y}$

$\frac{2 (2 y - 3) (y - 3)}{y^{3} - 6 y^{2} + 9 y}$

Simplify the denominator.

Factor $y$ out of $y^{3} - 6 y^{2} + 9 y$ .

Factor $y$ out of $y^{3}$ .

$\frac{2 (2 y - 3) (y - 3)}{y \cdot y^{2} - 6 y^{2} + 9 y}$

Factor $y$ out of $- 6 y^{2}$ .

$\frac{2 (2 y - 3) (y - 3)}{y \cdot y^{2} + y (- 6 y) + 9 y}$

Factor $y$ out of $9 y$ .

$\frac{2 (2 y - 3) (y - 3)}{y \cdot y^{2} + y (- 6 y) + y \cdot 9}$

Factor $y$ out of $y \cdot y^{2} + y (- 6 y)$ .

$\frac{2 (2 y - 3) (y - 3)}{y (y^{2} - 6 y) + y \cdot 9}$

Factor $y$ out of $y (y^{2} - 6 y) + y \cdot 9$ .

$\frac{2 (2 y - 3) (y - 3)}{y (y^{2} - 6 y + 9)}$

Factor using the perfect square rule.

Rewrite $9$ as $3^{2}$ .

$\frac{2 (2 y - 3) (y - 3)}{y (y^{2} - 6 y + 3^{2})}$

Check that the middle term is two times the product of the numbers being squared in the first term and third term.

$6 y = 2 \cdot y \cdot 3$

Rewrite the polynomial.

$\frac{2 (2 y - 3) (y - 3)}{y (y^{2} - 2 \cdot y \cdot 3 + 3^{2})}$

Factor using the perfect square trinomial rule $a^{2} - 2 a b + b^{2} = {(a - b)}^{2}$ , where $a = y$ and $b = 3$ .

$\frac{2 (2 y - 3) (y - 3)}{y {(y - 3)}^{2}}$

Cancel the common factor of $y - 3$ and ${(y - 3)}^{2}$ .

Factor $y - 3$ out of $2 (2 y - 3) (y - 3)$ .

$\frac{(y - 3) (2 (2 y - 3))}{y {(y - 3)}^{2}}$

Cancel the common factors.

Factor $y - 3$ out of $y {(y - 3)}^{2}$ .

$\frac{(y - 3) (2 (2 y - 3))}{(y - 3) (y (y - 3))}$

Cancel the common factor.

$\frac{(y - 3) (2 (2 y - 3))}{(y - 3) (y (y - 3))}$

Rewrite the expression.

$\frac{2 (2 y - 3)}{y (y - 3)}$

Simplify (4y^2-18y+18)/(y^3-6y^2+9y)

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