Simplify -5 cube root of 14p*-4 cube root of 4p^3

$- 5 \sqrt[3]{14 p} \cdot - 4 \sqrt[3]{4 p^{3}}$

Reorder $4$ and $p^{3}$ .

$- 5 \sqrt[3]{14 p} \cdot (- 4 \sqrt[3]{p^{3} \cdot 4})$

Pull terms out from under the radical.

$- 5 \sqrt[3]{14 p} \cdot (- 4 (p \sqrt[3]{4}))$

Multiply $- 5 \sqrt[3]{14 p} (- 4 p \sqrt[3]{4})$ .

Multiply $- 4$ by $- 5$ .

$20 \sqrt[3]{14 p} (p \sqrt[3]{4})$

Combine using the product rule for radicals.

$20 (p \sqrt[3]{14 p \cdot 4})$

Multiply $4$ by $14$ .

$20 (p \sqrt[3]{56 p})$

Rewrite $56 p$ as $2^{3} \cdot (7 p)$ .

Factor $8$ out of $56$ .

$20 (p \sqrt[3]{8 (7) p})$

Rewrite $8$ as $2^{3}$ .

$20 (p \sqrt[3]{2^{3} \cdot 7 p})$

Add parentheses.

$20 (p \sqrt[3]{2^{3} \cdot (7 p)})$

Pull terms out from under the radical.

$20 (p (2 \sqrt[3]{7 p}))$

Simplify the expression.

Rewrite using the commutative property of multiplication.

$20 (2 p \sqrt[3]{7 p})$

Multiply $2$ by $20$ .

$40 p \sqrt[3]{7 p}$