Simplify 5ii(-2i)

$5 i \cdot i \cdot (- 2 i)$

Step 1

Multiply $5 i i$ .

Raise $i$ to the power of $1$ .

$5 (i^{1} i) \cdot (- 2 i)$

Raise $i$ to the power of $1$ .

$5 (i^{1} i^{1}) \cdot (- 2 i)$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$5 i^{1 + 1} \cdot (- 2 i)$

Add $1$ and $1$ .

$5 i^{2} \cdot (- 2 i)$

Step 2

Rewrite $i^{2}$ as $- 1$ .

$5 \cdot - 1 \cdot (- 2 i)$

Step 3

Multiply $5$ by $- 1$ .

$- 5 \cdot (- 2 i)$

Step 4

Multiply $- 2$ by $- 5$ .

$10 i$

Simplify 5i*i*(-2i)