Simplify 6 cube root of 5+4 cube root of 625

$6 \sqrt[3]{5} + 4 \sqrt[3]{625}$

Step 1

Simplify each term.

Rewrite $625$ as $5^{3} \cdot 5$ .

Factor $125$ out of $625$ .

$6 \sqrt[3]{5} + 4 \sqrt[3]{125 (5)}$

Rewrite $125$ as $5^{3}$ .

$6 \sqrt[3]{5} + 4 \sqrt[3]{5^{3} \cdot 5}$

$6 \sqrt[3]{5} + 4 \sqrt[3]{5^{3} \cdot 5}$

Pull terms out from under the radical.

$6 \sqrt[3]{5} + 4 (5 \sqrt[3]{5})$

Multiply $5$ by $4$ .

$6 \sqrt[3]{5} + 20 \sqrt[3]{5}$

$6 \sqrt[3]{5} + 20 \sqrt[3]{5}$

Step 2

Add $6 \sqrt[3]{5}$ and $20 \sqrt[3]{5}$ .

$26 \sqrt[3]{5}$

Step 3

The result can be shown in multiple forms.

Exact Form:

$26 \sqrt[3]{5}$

Decimal Form:

$44.45937461 \dots$

Related Questions