Simplify (6-x-x^2)/(x^2-9)

$\frac{6 - x - x^{2}}{x^{2} - 9}$

Factor by grouping.

Reorder terms.

$\frac{- x^{2} - x + 6}{x^{2} - 9}$

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = - 1 \cdot 6 = - 6$ and whose sum is $b = - 1$ .

Factor $- 1$ out of $- x$ .

$\frac{- x^{2} - (x) + 6}{x^{2} - 9}$

Rewrite $- 1$ as $2$ plus $- 3$

$\frac{- x^{2} + (2 - 3) x + 6}{x^{2} - 9}$

Apply the distributive property.

$\frac{- x^{2} + 2 x - 3 x + 6}{x^{2} - 9}$

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$\frac{(- x^{2} + 2 x) - 3 x + 6}{x^{2} - 9}$

Factor out the greatest common factor (GCF) from each group.

$\frac{x (- x + 2) + 3 (- x + 2)}{x^{2} - 9}$

Factor the polynomial by factoring out the greatest common factor, $- x + 2$ .

$\frac{(- x + 2) (x + 3)}{x^{2} - 9}$

Simplify the denominator.

Rewrite $9$ as $3^{2}$ .

$\frac{(- x + 2) (x + 3)}{x^{2} - 3^{2}}$

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x$ and $b = 3$ .

$\frac{(- x + 2) (x + 3)}{(x + 3) (x - 3)}$

Simplify terms.

Cancel the common factor of $x + 3$ .

Cancel the common factor.

$\frac{(- x + 2) (x + 3)}{(x + 3) (x - 3)}$

Rewrite the expression.

$\frac{- x + 2}{x - 3}$

Factor $- 1$ out of $- x$ .

$\frac{- (x) + 2}{x - 3}$

Rewrite $2$ as $- 1 (- 2)$ .

$\frac{- (x) - 1 (- 2)}{x - 3}$

Factor $- 1$ out of $- (x) - 1 (- 2)$ .

$\frac{- (x - 2)}{x - 3}$

Simplify the expression.

Rewrite $- (x - 2)$ as $- 1 (x - 2)$ .

$\frac{- 1 (x - 2)}{x - 3}$

Move the negative in front of the fraction.

$- \frac{x - 2}{x - 3}$

Simplify (6-x-x^2)/(x^2-9)

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