Simplify 6i*(-4i)+8

$6 i \cdot (- 4 i) + 8$

Step 1

Simplify each term.

Multiply $6 i (- 4 i)$ .

Multiply $- 4$ by $6$ .

$- 24 i i + 8$

Raise $i$ to the power of $1$ .

$- 24 (i^{1} i) + 8$

Raise $i$ to the power of $1$ .

$- 24 (i^{1} i^{1}) + 8$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$- 24 i^{1 + 1} + 8$

Add $1$ and $1$ .

$- 24 i^{2} + 8$

Rewrite $i^{2}$ as $- 1$ .

$- 24 \cdot - 1 + 8$

Multiply $- 24$ by $- 1$ .

$24 + 8$

Step 2

Add $24$ and $8$ .

$32$