Simplify (6x^-2y^3)/(z^-4)

$\frac{6 x^{- 2} y^{3}}{z^{- 4}}$

Step 1

Move $x^{- 2}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{6 y^{3}}{z^{- 4} x^{2}}$

Step 2

Move $z^{- 4}$ to the numerator using the negative exponent rule $\frac{1}{b^{- n}} = b^{n}$ .

$\frac{6 y^{3} z^{4}}{x^{2}}$