Simplify (6x^3-4x^2+x-9)-(3x^2+7x+3)

$(6 x^{3} - 4 x^{2} + x - 9) - (3 x^{2} + 7 x + 3)$

Step 1

Simplify each term.

Apply the distributive property.

$6 x^{3} - 4 x^{2} + x - 9 - (3 x^{2}) - (7 x) - 1 \cdot 3$

Simplify.

Multiply $3$ by $- 1$ .

$6 x^{3} - 4 x^{2} + x - 9 - 3 x^{2} - (7 x) - 1 \cdot 3$

Multiply $7$ by $- 1$ .

$6 x^{3} - 4 x^{2} + x - 9 - 3 x^{2} - 7 x - 1 \cdot 3$

Multiply $- 1$ by $3$ .

$6 x^{3} - 4 x^{2} + x - 9 - 3 x^{2} - 7 x - 3$

Step 2

Simplify by adding terms.

Subtract $3 x^{2}$ from $- 4 x^{2}$ .

$6 x^{3} - 7 x^{2} + x - 9 - 7 x - 3$

Subtract $7 x$ from $x$ .

$6 x^{3} - 7 x^{2} - 6 x - 9 - 3$

Subtract $3$ from $- 9$ .

$6 x^{3} - 7 x^{2} - 6 x - 12$