Simplify (7-13x^3-11x)-(2x^3+8-4x^5)

$(7 - 13 x^{3} - 11 x) - (2 x^{3} + 8 - 4 x^{5})$

Step 1

Simplify each term.

Apply the distributive property.

$7 - 13 x^{3} - 11 x - (2 x^{3}) - 1 \cdot 8 - (- 4 x^{5})$

Simplify.

Multiply $2$ by $- 1$ .

$7 - 13 x^{3} - 11 x - 2 x^{3} - 1 \cdot 8 - (- 4 x^{5})$

Multiply $- 1$ by $8$ .

$7 - 13 x^{3} - 11 x - 2 x^{3} - 8 - (- 4 x^{5})$

Multiply $- 4$ by $- 1$ .

$7 - 13 x^{3} - 11 x - 2 x^{3} - 8 + 4 x^{5}$

Step 2

Simplify by adding terms.

Subtract $8$ from $7$ .

$- 13 x^{3} - 11 x - 2 x^{3} - 1 + 4 x^{5}$

Subtract $2 x^{3}$ from $- 13 x^{3}$ .

$- 15 x^{3} - 11 x - 1 + 4 x^{5}$

Simplify the expression.

Move $- 1$ .

$- 15 x^{3} - 11 x + 4 x^{5} - 1$

Move $- 11 x$ .

$- 15 x^{3} + 4 x^{5} - 11 x - 1$

Reorder $- 15 x^{3}$ and $4 x^{5}$ .

$4 x^{5} - 15 x^{3} - 11 x - 1$