Simplify (7-3i^2)(i^4-6)

$(7 - 3 i^{2}) (i^{4} - 6)$

Simplify each term.

Rewrite $i^{2}$ as $- 1$ .

$(7 - 3 \cdot - 1) (i^{4} - 6)$

Multiply $- 3$ by $- 1$ .

$(7 + 3) (i^{4} - 6)$

$(7 + 3) (i^{4} - 6)$

Add $7$ and $3$ .

$10 (i^{4} - 6)$

Rewrite $i^{4}$ as $1$ .

Rewrite $i^{4}$ as ${(i^{2})}^{2}$ .

$10 ({(i^{2})}^{2} - 6)$

Rewrite $i^{2}$ as $- 1$ .

$10 ({(- 1)}^{2} - 6)$

Raise $- 1$ to the power of $2$ .

$10 (1 - 6)$

$10 (1 - 6)$

Subtract $6$ from $1$ .

$10 \cdot - 5$

Multiply $10$ by $- 5$ .

$- 50$

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