Simplify 7 cube root of m^7+3m^(7/3)

$7 \sqrt[3]{m^{7}} + 3 m^{\frac{7}{3}}$

Rewrite $m^{7}$ as ${(m^{2})}^{3} m$ .

Factor out $m^{6}$ .

$7 \sqrt[3]{m^{6} m} + 3 m^{\frac{7}{3}}$

Rewrite $m^{6}$ as ${(m^{2})}^{3}$ .

$7 \sqrt[3]{{(m^{2})}^{3} m} + 3 m^{\frac{7}{3}}$

Pull terms out from under the radical.

$7 m^{2} \sqrt[3]{m} + 3 m^{\frac{7}{3}}$