Simplify 7 fifth root of b^5n-2b10 root of n^2

$7 \sqrt[5]{b^{5} n} - 2 b \sqrt[10]{n^{2}}$

Step 1

Simplify each term.

Pull terms out from under the radical.

$7 (b \sqrt[5]{n}) - 2 b \sqrt[10]{n^{2}}$

Rewrite $\sqrt[10]{n^{2}}$ as $\sqrt[5]{\sqrt{n^{2}}}$ .

$7 b \sqrt[5]{n} - 2 b \sqrt[5]{\sqrt{n^{2}}}$

Pull terms out from under the radical, assuming positive real numbers.

$7 b \sqrt[5]{n} - 2 b \sqrt[5]{n}$

Step 2

Subtract $2 b \sqrt[5]{n}$ from $7 b \sqrt[5]{n}$ .

$5 b \sqrt[5]{n}$