Simplify 7 square root of 96x^3

$7 \sqrt{96 x^{3}}$

Step 1

Rewrite $96 x^{3}$ as ${(4 x)}^{2} \cdot (6 x)$ .

Factor $16$ out of $96$ .

$7 \sqrt{16 (6) x^{3}}$

Rewrite $16$ as $4^{2}$ .

$7 \sqrt{4^{2} \cdot 6 x^{3}}$

Factor out $x^{2}$ .

$7 \sqrt{4^{2} \cdot 6 (x^{2} x)}$

Move $6$ .

$7 \sqrt{4^{2} x^{2} \cdot 6 x}$

Rewrite $4^{2} x^{2}$ as ${(4 x)}^{2}$ .

$7 \sqrt{{(4 x)}^{2} \cdot 6 x}$

Add parentheses.

$7 \sqrt{{(4 x)}^{2} \cdot (6 x)}$

$7 \sqrt{{(4 x)}^{2} \cdot (6 x)}$

Step 2

Pull terms out from under the radical.

$7 (4 x \sqrt{6 x})$

Step 3

Multiply $4$ by $7$ .

$28 x \sqrt{6 x}$

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