Simplify (7x^3-x^2)/(2x^3)

$\frac{7 x^{3} - x^{2}}{2 x^{3}}$

Step 1

Factor $x^{2}$ out of $7 x^{3} - x^{2}$ .

Factor $x^{2}$ out of $7 x^{3}$ .

$\frac{x^{2} (7 x) - x^{2}}{2 x^{3}}$

Factor $x^{2}$ out of $- x^{2}$ .

$\frac{x^{2} (7 x) + x^{2} \cdot - 1}{2 x^{3}}$

Factor $x^{2}$ out of $x^{2} (7 x) + x^{2} \cdot - 1$ .

$\frac{x^{2} (7 x - 1)}{2 x^{3}}$

Step 2

Cancel the common factors.

Factor $x^{2}$ out of $2 x^{3}$ .

$\frac{x^{2} (7 x - 1)}{x^{2} (2 x)}$

Cancel the common factor.

$\frac{x^{2} (7 x - 1)}{x^{2} (2 x)}$

Rewrite the expression.

$\frac{7 x - 1}{2 x}$