Simplify (7x^3-x+4x^2-9)-(6x^2-4x^3+11)

$(7 x^{3} - x + 4 x^{2} - 9) - (6 x^{2} - 4 x^{3} + 11)$

Step 1

Simplify each term.

Apply the distributive property.

$7 x^{3} - x + 4 x^{2} - 9 - (6 x^{2}) - (- 4 x^{3}) - 1 \cdot 11$

Simplify.

Multiply $6$ by $- 1$ .

$7 x^{3} - x + 4 x^{2} - 9 - 6 x^{2} - (- 4 x^{3}) - 1 \cdot 11$

Multiply $- 4$ by $- 1$ .

$7 x^{3} - x + 4 x^{2} - 9 - 6 x^{2} + 4 x^{3} - 1 \cdot 11$

Multiply $- 1$ by $11$ .

$7 x^{3} - x + 4 x^{2} - 9 - 6 x^{2} + 4 x^{3} - 11$

Step 2

Simplify by adding terms.

Add $7 x^{3}$ and $4 x^{3}$ .

$11 x^{3} - x + 4 x^{2} - 9 - 6 x^{2} - 11$

Subtract $6 x^{2}$ from $4 x^{2}$ .

$11 x^{3} - x - 2 x^{2} - 9 - 11$

Simplify the expression.

Subtract $11$ from $- 9$ .

$11 x^{3} - x - 2 x^{2} - 20$

Move $- x$ .

$11 x^{3} - 2 x^{2} - x - 20$