Simplify (7x^-3y^-4)/(8z^-5)

$\frac{7 x^{- 3} y^{- 4}}{8 z^{- 5}}$

Move $x^{- 3}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{7 y^{- 4}}{8 z^{- 5} x^{3}}$

Move $y^{- 4}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{7}{8 z^{- 5} x^{3} y^{4}}$

Move $z^{- 5}$ to the numerator using the negative exponent rule $\frac{1}{b^{- n}} = b^{n}$ .

$\frac{7 z^{5}}{8 x^{3} y^{4}}$