Simplify (-8^-2)/(5^-1cd^0)

$\frac{- 8^{- 2}}{5^{- 1} c d^{0}}$

Step 1

Move $8^{- 2}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{- 1}{5^{- 1} c d^{0} \cdot 8^{2}}$

Step 2

Move $5^{- 1}$ to the numerator using the negative exponent rule $\frac{1}{b^{- n}} = b^{n}$ .

$\frac{- 1 \cdot 5}{c \cdot 8^{2}}$

Step 3

Multiply $- 1$ by $5$ .

$\frac{- 5}{c \cdot 8^{2}}$

Step 4

Raise $8$ to the power of $2$ .

$\frac{- 5}{c \cdot 64}$

Step 5

Move $64$ to the left of $c$ .

$\frac{- 5}{64 \cdot c}$

Step 6

Move the negative in front of the fraction.

$- \frac{5}{64 c}$