Simplify (8(9+x)^(1/3)-x(9+x)^(-2/3))/((9+x)^(2/3))

$\frac{8 {(9 + x)}^{\frac{1}{3}} - x {(9 + x)}^{- \frac{2}{3}}}{{(9 + x)}^{\frac{2}{3}}}$

Step 1

Simplify the numerator.

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{8 {(9 + x)}^{\frac{1}{3}} - x \frac{1}{{(9 + x)}^{\frac{2}{3}}}}{{(9 + x)}^{\frac{2}{3}}}$

Combine $\frac{1}{{(9 + x)}^{\frac{2}{3}}}$ and $x$ .

$\frac{8 {(9 + x)}^{\frac{1}{3}} - \frac{x}{{(9 + x)}^{\frac{2}{3}}}}{{(9 + x)}^{\frac{2}{3}}}$

To write $8 {(9 + x)}^{\frac{1}{3}}$ as a fraction with a common denominator, multiply by $\frac{{(9 + x)}^{\frac{2}{3}}}{{(9 + x)}^{\frac{2}{3}}}$ .

$\frac{\frac{8 {(9 + x)}^{\frac{1}{3}} {(9 + x)}^{\frac{2}{3}}}{{(9 + x)}^{\frac{2}{3}}} - \frac{x}{{(9 + x)}^{\frac{2}{3}}}}{{(9 + x)}^{\frac{2}{3}}}$

Combine the numerators over the common denominator.

$\frac{\frac{8 {(9 + x)}^{\frac{1}{3}} {(9 + x)}^{\frac{2}{3}} - x}{{(9 + x)}^{\frac{2}{3}}}}{{(9 + x)}^{\frac{2}{3}}}$

Reorder terms.

$\frac{\frac{8 {(9 + x)}^{\frac{2}{3}} {(9 + x)}^{\frac{1}{3}} - x}{{(x + 9)}^{\frac{2}{3}}}}{{(9 + x)}^{\frac{2}{3}}}$

Rewrite $\frac{8 {(9 + x)}^{\frac{2}{3}} {(9 + x)}^{\frac{1}{3}} - x}{{(x + 9)}^{\frac{2}{3}}}$ in a factored form.

Multiply ${(9 + x)}^{\frac{2}{3}}$ by ${(9 + x)}^{\frac{1}{3}}$ by adding the exponents.

Move ${(9 + x)}^{\frac{1}{3}}$ .

$\frac{\frac{8 ({(9 + x)}^{\frac{1}{3}} {(9 + x)}^{\frac{2}{3}}) - x}{{(x + 9)}^{\frac{2}{3}}}}{{(9 + x)}^{\frac{2}{3}}}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{\frac{8 {(9 + x)}^{\frac{1}{3} + \frac{2}{3}} - x}{{(x + 9)}^{\frac{2}{3}}}}{{(9 + x)}^{\frac{2}{3}}}$

Combine the numerators over the common denominator.

$\frac{\frac{8 {(9 + x)}^{\frac{1 + 2}{3}} - x}{{(x + 9)}^{\frac{2}{3}}}}{{(9 + x)}^{\frac{2}{3}}}$

Add $1$ and $2$ .

$\frac{\frac{8 {(9 + x)}^{\frac{3}{3}} - x}{{(x + 9)}^{\frac{2}{3}}}}{{(9 + x)}^{\frac{2}{3}}}$

Divide $3$ by $3$ .

$\frac{\frac{8 {(9 + x)}^{1} - x}{{(x + 9)}^{\frac{2}{3}}}}{{(9 + x)}^{\frac{2}{3}}}$

Simplify $8 {(9 + x)}^{1}$ .

$\frac{\frac{8 (9 + x) - x}{{(x + 9)}^{\frac{2}{3}}}}{{(9 + x)}^{\frac{2}{3}}}$

Apply the distributive property.

$\frac{\frac{8 \cdot 9 + 8 x - x}{{(x + 9)}^{\frac{2}{3}}}}{{(9 + x)}^{\frac{2}{3}}}$

Multiply $8$ by $9$ .

$\frac{\frac{72 + 8 x - x}{{(x + 9)}^{\frac{2}{3}}}}{{(9 + x)}^{\frac{2}{3}}}$

Subtract $x$ from $8 x$ .

$\frac{\frac{72 + 7 x}{{(x + 9)}^{\frac{2}{3}}}}{{(9 + x)}^{\frac{2}{3}}}$

Step 2

Multiply the numerator by the reciprocal of the denominator.

$\frac{72 + 7 x}{{(x + 9)}^{\frac{2}{3}}} \cdot \frac{1}{{(9 + x)}^{\frac{2}{3}}}$

Step 3

Multiply $\frac{72 + 7 x}{{(x + 9)}^{\frac{2}{3}}} \cdot \frac{1}{{(9 + x)}^{\frac{2}{3}}}$ .

Multiply $\frac{72 + 7 x}{{(x + 9)}^{\frac{2}{3}}}$ by $\frac{1}{{(9 + x)}^{\frac{2}{3}}}$ .

$\frac{72 + 7 x}{{(x + 9)}^{\frac{2}{3}} {(9 + x)}^{\frac{2}{3}}}$

Reorder terms.

$\frac{72 + 7 x}{{(x + 9)}^{\frac{2}{3}} {(x + 9)}^{\frac{2}{3}}}$

Multiply ${(x + 9)}^{\frac{2}{3}}$ by ${(x + 9)}^{\frac{2}{3}}$ by adding the exponents.

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{72 + 7 x}{{(x + 9)}^{\frac{2}{3} + \frac{2}{3}}}$

Combine the numerators over the common denominator.

$\frac{72 + 7 x}{{(x + 9)}^{\frac{2 + 2}{3}}}$

Add $2$ and $2$ .

$\frac{72 + 7 x}{{(x + 9)}^{\frac{4}{3}}}$

Simplify (8(9+x)^(1/3)-x(9+x)^(-2/3))/((9+x)^(2/3))

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