Simplify 8 cube root of x^4y-7x cube root of xy

$8 \sqrt[3]{x^{4} y} - 7 x \sqrt[3]{x y}$

Step 1

Simplify each term.

Rewrite $x^{4} y$ as $x^{3} (x y)$ .

Factor out $x^{3}$ .

$8 \sqrt[3]{x^{3} x y} - 7 x \sqrt[3]{x y}$

Add parentheses.

$8 \sqrt[3]{x^{3} (x y)} - 7 x \sqrt[3]{x y}$

Pull terms out from under the radical.

$8 x \sqrt[3]{x y} - 7 x \sqrt[3]{x y}$

Step 2

Simplify by adding terms.

Subtract $7 x \sqrt[3]{x y}$ from $8 x \sqrt[3]{x y}$ .

$1 x \sqrt[3]{x y}$

Multiply $x$ by $1$ .

$x \sqrt[3]{x y}$