Simplify (8y^-8)/(x^3y^-5)

$\frac{8 y^{- 8}}{x^{3} y^{- 5}}$

Step 1

Move $y^{- 8}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{8}{x^{3} y^{- 5} y^{8}}$

Step 2

Multiply $y^{- 5}$ by $y^{8}$ by adding the exponents.

Move $y^{8}$ .

$\frac{8}{x^{3} (y^{8} y^{- 5})}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{8}{x^{3} y^{8 - 5}}$

Subtract $5$ from $8$ .

$\frac{8}{x^{3} y^{3}}$