Simplify 9/((3d)^-3)

$\frac{9}{{(3 d)}^{- 3}}$

Step 1

Move ${(3 d)}^{- 3}$ to the numerator using the negative exponent rule $\frac{1}{b^{- n}} = b^{n}$ .

$9 {(3 d)}^{3}$

Step 2

Apply the product rule to $3 d$ .

$9 (3^{3} d^{3})$

Step 3

Raise $3$ to the power of $3$ .

$9 (27 d^{3})$

Step 4

Multiply $27$ by $9$ .

$243 d^{3}$