Simplify (9-3x)/(15-2x-x^2)

$\frac{9 - 3 x}{15 - 2 x - x^{2}}$

Step 1

Factor $3$ out of $9 - 3 x$ .

Factor $3$ out of $9$ .

$\frac{3 (3) - 3 x}{15 - 2 x - x^{2}}$

Factor $3$ out of $- 3 x$ .

$\frac{3 (3) + 3 (- x)}{15 - 2 x - x^{2}}$

Factor $3$ out of $3 (3) + 3 (- x)$ .

$\frac{3 (3 - x)}{15 - 2 x - x^{2}}$

Step 2

Simplify the denominator.

Rewrite $15$ as $16$ plus $- 1$

$\frac{3 (3 - x)}{16 - 1 - 2 x - x^{2}}$

Factor using the perfect square rule.

Rewrite $1$ as $1^{2}$ .

$\frac{3 (3 - x)}{16 - (1^{2} + 2 x + x^{2})}$

Check that the middle term is two times the product of the numbers being squared in the first term and third term.

$2 x = 2 \cdot 1 \cdot x$

Rewrite the polynomial.

$\frac{3 (3 - x)}{16 - (1^{2} + 2 \cdot 1 \cdot x + x^{2})}$

Factor using the perfect square trinomial rule $a^{2} + 2 a b + b^{2} = {(a + b)}^{2}$ , where $a = 1$ and $b = x$ .

$\frac{3 (3 - x)}{16 - {(1 + x)}^{2}}$

Rewrite $16$ as $4^{2}$ .

$\frac{3 (3 - x)}{4^{2} - {(1 + x)}^{2}}$

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 4$ and $b = 1 + x$ .

$\frac{3 (3 - x)}{(4 + 1 + x) (4 - (1 + x))}$

Simplify.

Add $4$ and $1$ .

$\frac{3 (3 - x)}{(5 + x) (4 - (1 + x))}$

Apply the distributive property.

$\frac{3 (3 - x)}{(5 + x) (4 - 1 \cdot 1 - x)}$

Multiply $- 1$ by $1$ .

$\frac{3 (3 - x)}{(5 + x) (4 - 1 - x)}$

Subtract $1$ from $4$ .

$\frac{3 (3 - x)}{(5 + x) (3 - x)}$

Step 3

Cancel the common factor of $3 - x$ .

Cancel the common factor.

$\frac{3 (3 - x)}{(5 + x) (3 - x)}$

Rewrite the expression.

$\frac{3}{5 + x}$

Simplify (9-3x)/(15-2x-x^2)

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