Simplify (-9c)^0+(d)^0+2(8e)^0

${(- 9 c)}^{0} + {(d)}^{0} + 2 {(8 e)}^{0}$

Simplify each term.

Apply the product rule to $- 9 c$ .

${(- 9)}^{0} c^{0} + {(d)}^{0} + 2 {(8 e)}^{0}$

Anything raised to $0$ is $1$ .

$1 c^{0} + {(d)}^{0} + 2 {(8 e)}^{0}$

Multiply $c^{0}$ by $1$ .

$c^{0} + {(d)}^{0} + 2 {(8 e)}^{0}$

Anything raised to $0$ is $1$ .

$1 + {(d)}^{0} + 2 {(8 e)}^{0}$

Anything raised to $0$ is $1$ .

$1 + 1 + 2 {(8 e)}^{0}$

Apply the product rule to $8 e$ .

$1 + 1 + 2 (8^{0} e^{0})$

Anything raised to $0$ is $1$ .

$1 + 1 + 2 (1 e^{0})$

Multiply $e^{0}$ by $1$ .

$1 + 1 + 2 e^{0}$

Anything raised to $0$ is $1$ .

$1 + 1 + 2 \cdot 1$

Multiply $2$ by $1$ .

$1 + 1 + 2$

$1 + 1 + 2$

Simplify by adding numbers.

Add $1$ and $1$ .

$2 + 2$

Add $2$ and $2$ .

$4$

$4$

Related Questions