Simplify 9x^0y^-3

$9 x^{0} y^{- 3}$

Anything raised to $0$ is $1$ .

$9 \cdot 1 y^{- 3}$

Multiply $9$ by $1$ .

$9 y^{- 3}$

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$9 \frac{1}{y^{3}}$

Combine $9$ and $\frac{1}{y^{3}}$ .

$\frac{9}{y^{3}}$