Simplify (a^2+5a+7)(1-a)^-1

$(a^{2} + 5 a + 7) {(1 - a)}^{- 1}$

Step 1

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$(a^{2} + 5 a + 7) \frac{1}{1 - a}$

Step 2

Multiply $a^{2} + 5 a + 7$ by $\frac{1}{1 - a}$ .

$\frac{a^{2} + 5 a + 7}{1 - a}$