Simplify (-bc+3b-4c)+(bc+3b+4c)

$(- b c + 3 b - 4 c) + (b c + 3 b + 4 c)$

Remove parentheses.

$- b c + 3 b - 4 c + b c + 3 b + 4 c$

Combine the opposite terms in $- b c + 3 b - 4 c + b c + 3 b + 4 c$ .

Add $- b c$ and $b c$ .

$3 b - 4 c + 0 + 3 b + 4 c$

Add $3 b - 4 c$ and $0$ .

$3 b - 4 c + 3 b + 4 c$

Add $- 4 c$ and $4 c$ .

$3 b + 3 b + 0$

Add $3 b + 3 b$ and $0$ .

$3 b + 3 b$

Add $3 b$ and $3 b$ .

$6 b$