Simplify/Condense 3* log base 2 of p+7* log base 2 of q

$3 \cdot \log_{2} (p) + 7 \cdot \log_{2} (q)$

Step 1

Simplify each term.

Simplify $3 \log_{2} (p)$ by moving $3$ inside the logarithm.

$\log_{2} (p^{3}) + 7 \cdot \log_{2} (q)$

Simplify $7 \log_{2} (q)$ by moving $7$ inside the logarithm.

$\log_{2} (p^{3}) + \log_{2} (q^{7})$

Step 2

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{2} (p^{3} q^{7})$