Simplify/Condense log base 12 of 6+ log base 12 of 2

$\log_{12} (6) + \log_{12} (2)$

Step 1

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{12} (6 \cdot 2)$

Step 2

Multiply $6$ by $2$ .

$\log_{12} (12)$

Step 3

Logarithm base $12$ of $12$ is $1$ .

$1$